Correct. The basic scenario is that there is a car behind one door and a goat behind two doors, and you don't know which is which but the game show host does. If you pick the door with the car, you win the car. The host let's you pick a door, then opens one of the two doors you didn't pick, revealing a goat. The host then offers you one last chance to switch your pick from your original door to the other remaining closed door.
The Monty Hall problem states that you should always switch your pick, and that by doing so you will double your chances of winning the car.
Which, intuitively, that's nonsense. Your choice has no actual impact on the reality of the situation. You're guessing blindly the same as before, it's just now that you have a one-in-two chance of guessing the right door instead of a one-in-three chance.
EXCEPT
During your first round of choosing, you had a 1/3 chance of guessing the car vs a 2/3 chance of guessing a goat, if you were only allowed that one guess. But once it's narrowed down to two doors, one with a goat and one with a car, you're now guaranteed to get the exact opposite outcome of what your original guess would have been if you switch. So if you stick with your first choice, you still have a 1/3 chance of getting the car and 2/3 chance of getting a goat. But if you switch, then suddenly that becomes a 1/3 chance of getting a goat, and a 2/3 chance of getting the car.
It's bullshit and I hate it so much.